作业帮[(1/3)^(n+1)-(1/2)^(n+1)]/[(1/3)^(n+1)+(1/2)^(n-1)]的极限等于( )A)-4 B)1/3 C)0 D)-1/4
来源：学生作业帮助网 编辑：作业帮 时间：2024/11/02 22:23:05
![[(1/3)^(n+1)-(1/2)^(n+1)]/[(1/3)^(n+1)+(1/2)^(n-1)]的极限等于( )A)-4 B)1/3 C)0 D)-1/4](/uploads/image/z/11057152-40-2.jpg?t=%5B%281%2F3%29%5E%28n%2B1%29-%281%2F2%29%5E%28n%2B1%29%5D%2F%5B%281%2F3%29%5E%28n%2B1%29%2B%281%2F2%29%5E%28n-1%29%5D%E7%9A%84%E6%9E%81%E9%99%90%E7%AD%89%E4%BA%8E%28+%29A%29-4+B%291%2F3+C%290+D%29-1%2F4)
x)076X}dm.Pg_Μ|m]}
&
N@
Κ
.&6IE1 lv; lh mON >r'"[U?Ɏ]t uNދm@;M_|gӷ)H@Mk66Mladz]l !`8ӃXuOv b
~ھܥOv=nhB2 4
[(1/3)^(n+1)-(1/2)^(n+1)]/[(1/3)^(n+1)+(1/2)^(n-1)]的极限等于( )A)-4 B)1/3 C)0 D)-1/4
[(1/3)^(n+1)-(1/2)^(n+1)]/[(1/3)^(n+1)+(1/2)^(n-1)]的极限等于( )
A)-4 B)1/3 C)0 D)-1/4
[(1/3)^(n+1)-(1/2)^(n+1)]/[(1/3)^(n+1)+(1/2)^(n-1)]的极限等于( )A)-4 B)1/3 C)0 D)-1/4
分子分母同除以(1/2)^(n+1)],分子变为（2/3）^(n+1)-1,n趋于无穷时,（2/3）^(n+1)趋于0,分子为-1.同理分析分母为4.答案是D
A，分子分母同时乘以2^(n+1)就可以看出来了。
证明不等式：(1/n)^n+(2/n)^n+(3/n)^n+.+(n/n)^n
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
[3n(n+1)+n(n+1)(2n+1)]/6+n(n+2)化简
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简n分之n-1+n分之n-2+n分之n-3+.+n分之1
化简(n+1)(n+2)(n+3)
当n为正偶数,求证n/(n-1)+n(n-2)/(n-1)(n-3)+...+n(n-2).2/(n-1)(n-3)...1=n
2^n/n*(n+1)
lim2^n +3^n/2^n+1+3^n+1
n(n+1)(n+2)(n+3)+1 因式分解
n(n+1)(n+2)(n+3)+1等于多少
3(n-1)(n+3)-2(n-5)(n-2)
lim(n+3)(4-n)/(n-1)(3-2n)
lim(n^3+n)/(n^4-3n^2+1)
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(2^n+3^n)^1
(n趋向无穷)
级数n/(n+1)(n+2)(n+3)和是多少
n*1+n*2+n*3+n*4.求公式