已知|2x-3y+2|+ 根号2y-6 =0,求5x-6y.
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已知|2x-3y+2|+ 根号2y-6 =0,求5x-6y.
已知|2x-3y+2|+ 根号2y-6 =0,求5x-6y.
已知|2x-3y+2|+ 根号2y-6 =0,求5x-6y.
因为|2x-3y+2|≥0,根号2y-6≥0
|2x-3y+2|+ 根号2y-6 =0
所以2x-3y+2=0,2y-6=0
于是x=3.5,y=3
所以5x-6y=-0.5
|2x-3y+2|+ √(2y-6) =0
√(2y-6) =0
y=3
|2x-3y+2|=0
2x-3y+2=0
2x-3*3+2=0
2x-7=0
x=7/2
5x-6y
=5*7/2-6*3
=35/2-18
=-1/2
这个题考的是绝对值加根号等于零,则绝对值里的式子等于零,被开放数或式等于零
因为|2x-3y+2|+根号下2y-6=0
所以2x-3y+2=0
2y-6=0
则:y=3 x=7/2
则:5x-6y=35/2-18
=-1/2
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