已知/x+2y/+根号3x-7+(5y+z)²=0 求x-3y+4z的值
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已知/x+2y/+根号3x-7+(5y+z)²=0 求x-3y+4z的值
已知/x+2y/+根号3x-7+(5y+z)²=0 求x-3y+4z的值
已知/x+2y/+根号3x-7+(5y+z)²=0 求x-3y+4z的值
楼主好
因为这三个都大于等于0,所以相加等于0,只只能是/x+2y/=0,根号3x-7=0,(5y+z)²=0,这样先求出x的值,再解得y和z的值
/x+2y/+根号3x-7+(5y+z)²=0 可以得出:
/x+2y/=0 即 x+2y=0
根号3x-7=0 即 3x-7=0
(5y+z)²=0 即5y+z=0
x=7/3
y=-7/6
z=35/6
x-3y+4z=175/6
∵/x+2y/+根号3x-7+(5y+z)²=0
∴x+2y=0 3x-7=0 5y+z=0
∴x=7/3 y=-7/6 z=35/6
∴x-3y+4z
=7/3-3(-7/6)+4(35/6)
=7/3+21/6+140/6
=14/6+21/6+140/6
=175/6
/x+2y/+根号3x-7+(5y+z)²=0 只有/x+2y/=0、根号3x-7=0和(5y+z)²=0,再求x、y、z的值即可。
所以 x=7/3,z=-7/6,x=7/30