sin2a+sina/cos2a+cosa+1=
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![sin2a+sina/cos2a+cosa+1=](/uploads/image/z/1116789-69-9.jpg?t=sin2a%2Bsina%2Fcos2a%2Bcosa%2B1%3D)
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sin2a+sina/cos2a+cosa+1=
sin2a+sina/cos2a+cosa+1=
sin2a+sina/cos2a+cosa+1=
sin2a+sina/cos2a+cosa+1
=(2sinacosa+sina)/(2cos²a+cosa)
=sina(2cosa+1)/[cosa(2cosa+1)]
=sina/cosa
=tana
题目输入不清楚。