作业帮一道C++题目 设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ ）.为什么C设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ C）.A.0,0 B.0,1 C.1,0 D.1,1
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![一道C++题目 设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ ）.为什么C设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ C）.A.0,0 B.0,1 C.1,0 D.1,1](/uploads/image/z/11178268-52-8.jpg?t=%E4%B8%80%E9%81%93C%2B%2B%E9%A2%98%E7%9B%AE+%E8%AE%BE%E5%8F%98%E9%87%8Fm%2Cn%2Ca%2Cb%2Cc%2Cd%E5%9D%87%E4%B8%BA0%2C%E6%89%A7%E8%A1%8C%28m+%3D+a%3D%3Db%29%7C%7C%28n%3Dc%3D%3Dd%29%E5%90%8E%2Cm%2Cn%E7%9A%84%E5%80%BC%E6%98%AF%5B%E7%9F%AD%E8%B7%AF%5D%EF%BC%88+%EF%BC%89.%E4%B8%BA%E4%BB%80%E4%B9%88C%E8%AE%BE%E5%8F%98%E9%87%8Fm%2Cn%2Ca%2Cb%2Cc%2Cd%E5%9D%87%E4%B8%BA0%2C%E6%89%A7%E8%A1%8C%28m+%3D+a%3D%3Db%29%7C%7C%28n%3Dc%3D%3Dd%29%E5%90%8E%2Cm%2Cn%E7%9A%84%E5%80%BC%E6%98%AF%5B%E7%9F%AD%E8%B7%AF%5D%EF%BC%88+C%EF%BC%89.A.0%2C0+B.0%2C1+C.1%2C0+D.1%2C1)
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一道C++题目 设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ ）.为什么C设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ C）.A.0,0 B.0,1 C.1,0 D.1,1
一道C++题目 设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ ）.为什么C
设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ C）.
A.0,0 B.0,1 C.1,0 D.1,1
一道C++题目 设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ ）.为什么C设变量m,n,a,b,c,d均为0,执行(m = a==b)||(n=c==d)后,m,n的值是[短路]（ C）.A.0,0 B.0,1 C.1,0 D.1,1
逻辑运算符||从左至右计算,a==b的bool值为1,则m=1,由于左边的操作数为1,则停止运算.因为此时已经可以判定逻辑表达式结果为真.所以m=1,n=0