#includeusing namespace std;void f(int a,int *b,int &c,int*& d){a = 1;*b = 2;c = 3;*d = 4;}int main(){\x05int a = 0;\x05int *b = &a;\x05int &c = a;\x05int *&d = b;\x05f(a,b,c,d);\x05cout
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![#includeusing namespace std;void f(int a,int *b,int &c,int*& d){a = 1;*b = 2;c = 3;*d = 4;}int main(){\x05int a = 0;\x05int *b = &a;\x05int &c = a;\x05int *&d = b;\x05f(a,b,c,d);\x05cout](/uploads/image/z/11232968-32-8.jpg?t=%23includeusing+namespace+std%3Bvoid+f%28int+a%2Cint+%2Ab%2Cint+%26c%2Cint%2A%26+d%29%7Ba+%3D+1%3B%2Ab+%3D+2%3Bc+%3D+3%3B%2Ad+%3D+4%3B%7Dint+main%28%29%7B%5Cx05int+a+%3D+0%3B%5Cx05int+%2Ab+%3D+%26a%3B%5Cx05int+%26c+%3D+a%3B%5Cx05int+%2A%26d+%3D+b%3B%5Cx05f%28a%2Cb%2Cc%2Cd%29%3B%5Cx05cout)
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#includeusing namespace std;void f(int a,int *b,int &c,int*& d){a = 1;*b = 2;c = 3;*d = 4;}int main(){\x05int a = 0;\x05int *b = &a;\x05int &c = a;\x05int *&d = b;\x05f(a,b,c,d);\x05cout
#includeusing namespace std;
void f(int a,int *b,int &c,int*& d)
{
a = 1;
*b = 2;
c = 3;
*d = 4;
}
int main()
{\x05int a = 0;
\x05int *b = &a;
\x05int &c = a;
\x05int *&d = b;
\x05f(a,b,c,d);
\x05cout
#includeusing namespace std;void f(int a,int *b,int &c,int*& d){a = 1;*b = 2;c = 3;*d = 4;}int main(){\x05int a = 0;\x05int *b = &a;\x05int &c = a;\x05int *&d = b;\x05f(a,b,c,d);\x05cout
我告诉你吧,你在主函数里的操作导致4个变量同时指向了同一块内存空间,而你的f函数只能修改第4个实参d,所以当d改变的时候,和b指向同一空间的其他3实参都变了