已知m和n是方程x²+3x-7=0的两根,则m²+4m+n=?
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已知m和n是方程x²+3x-7=0的两根,则m²+4m+n=?
已知m和n是方程x²+3x-7=0的两根,则m²+4m+n=?
已知m和n是方程x²+3x-7=0的两根,则m²+4m+n=?
设m,n是一元二次方程x²+3x-7=0的两个根,
则m²+3m-7=0,m²+3m=7;
m+n=-b/a=-3,[韦达定理]
m²+4m+n
=m²+3m+(m+n)
=7+(-3)
=4
谢谢,祝你学习进步!
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