(2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=?

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(2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=?
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(2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=?
(2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=?

(2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=?
(2-1)(2+1)(2^2+1)(2^4)...(2^64+1) + 1
=(2² - 1)(2² + 1)(2⁴+ 1) .(2^64+1) + 1
= .
=(2^64 - 1) (2^64+1) + 1
=(2^128 - 1) + 1
= 2^128

1 2 1 2 () () ()() 1+1/2^2 (2-×)(1-×)=×-2-2(2-×)(1-×) 1+2+1+2+1+2+1+2+1+2+1+2+1+2 =( )*( ) =() 1/2+1/2*2+1/2*2*2+1/2*2*2*2+.+1/2*n 比如2^1、2^2? 2 1 -2 -3 2”表示“【1,2)” 谁能解便计算这道题1+2+2+2+1+2+2+2+2+2+1+1 1/2^-2=? 2i/2-1 loga(1/2)>2 (x+1/2)2 1,2, 1/2 1、2、 1 2 1+2?