(2m-3n)^2-2m+3n
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![(2m-3n)^2-2m+3n](/uploads/image/z/1124249-41-9.jpg?t=%282m-3n%29%5E2-2m%2B3n)
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(2m-3n)^2-2m+3n
(2m-3n)^2-2m+3n
(2m-3n)^2-2m+3n
(2m-3n)^2-2m+3n=(2m-3n)^2-(2m-3n)=(2m-3n)(2m-3n-1)
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(2m-3n)^2-2m+3n
=(2m-3n)^2-(2m-3n)
=(2m-3n-1)(2m-3n)
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4m(m-n)^2+4n(n-m)^3
2(m-n)的2次-(m+n)(m-2n)-3n(n-m)
2m-3n-m+2n
(m-n)3-(2n-m)3
(3m-n)(m-2n)=()
(m+2n)(m-3n)
(m-3n)(2m+n)
约分(m-n)^2/(n-m)^3
分解因式(2m-n)(2m-n)(2m-n)+3n(n-2m)(n-2m)
已知3m=2n,则m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=?