﹣¼π<α﹤¾π sin(¼﹣α)=√5/5 sinα=

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﹣¼π<α﹤¾π sin(¼﹣α)=√5/5 sinα=
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﹣¼π<α﹤¾π sin(¼﹣α)=√5/5 sinα=
﹣¼π<α﹤¾π sin(¼﹣α)=√5/5 sinα=

﹣¼π<α﹤¾π sin(¼﹣α)=√5/5 sinα=
¼π<α﹤¾π
sin(¼π﹣α)=√5/5
是不是少了一个π
-¼π<α﹤¾π
-π/2<π/4-a<π/2
cos(π/4-a)>0
cos(π/4-a)=2√5/5
sina=sin[π/4-(π/4-a)]
=sinπ/4cos(π/4-a)-sin(π/4-a)cosπ/4
=(√2/2)[2√5/5-√5/5]
=√10/10