4-m²n²+2mn
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4-m²n²+2mn
4-m²n²+2mn
4-m²n²+2mn
4-m²n²+2mn
=5-(m²n²-2mn+1)
=5-(mn-1)²
=(√5+mn-1)(√5-mn+1)
如果本题有什么不明白可以追问,
=5-(1-2mn+m²n²)
=5-(1-mn)²
=(√5+1-mn)(√5-1+mn)
4-m²-n²+2mn
=4-(m²-2mn+n²)
=2²-(m-n)²
=[2+(m-n)][2-(m-n)]
=(2+m-n)(2-m+n)
-(mn-1)的平方+3