如图,直角梯形ABCD中,AD‖BC,∠BCD=90°且CD=2AD,过点D作DE‖AB,交∠BCD的平分线于点E,连接BE.(1)求证:BC=CD.(2)将△BCE绕点C,顺时针旋转90°得到△DCG,连接EG.求证:CD垂直平分EG.(3)延长BE交CD于
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![如图,直角梯形ABCD中,AD‖BC,∠BCD=90°且CD=2AD,过点D作DE‖AB,交∠BCD的平分线于点E,连接BE.(1)求证:BC=CD.(2)将△BCE绕点C,顺时针旋转90°得到△DCG,连接EG.求证:CD垂直平分EG.(3)延长BE交CD于](/uploads/image/z/1128541-13-1.jpg?t=%E5%A6%82%E5%9B%BE%2C%E7%9B%B4%E8%A7%92%E6%A2%AF%E5%BD%A2ABCD%E4%B8%AD%2CAD%E2%80%96BC%2C%E2%88%A0BCD%3D90%C2%B0%E4%B8%94CD%3D2AD%2C%E8%BF%87%E7%82%B9D%E4%BD%9CDE%E2%80%96AB%2C%E4%BA%A4%E2%88%A0BCD%E7%9A%84%E5%B9%B3%E5%88%86%E7%BA%BF%E4%BA%8E%E7%82%B9E%2C%E8%BF%9E%E6%8E%A5BE.%EF%BC%881%EF%BC%89%E6%B1%82%E8%AF%81%EF%BC%9ABC%3DCD.%EF%BC%882%EF%BC%89%E5%B0%86%E2%96%B3BCE%E7%BB%95%E7%82%B9C%2C%E9%A1%BA%E6%97%B6%E9%92%88%E6%97%8B%E8%BD%AC90%C2%B0%E5%BE%97%E5%88%B0%E2%96%B3DCG%2C%E8%BF%9E%E6%8E%A5EG.%E6%B1%82%E8%AF%81%EF%BC%9ACD%E5%9E%82%E7%9B%B4%E5%B9%B3%E5%88%86EG.%EF%BC%883%EF%BC%89%E5%BB%B6%E9%95%BFBE%E4%BA%A4CD%E4%BA%8E)
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