已知y1=x²-2x+3,y2=3x-1当x为何值时,y1=y2?

已知y1=x²-2x+3,y2=3x-1当x为何值时,y1=y2?
已知y1=x²-2x+3,y2=3x-1当x为何值时,y1=y2?

已知y1=x²-2x+3,y2=3x-1当x为何值时,y1=y2?
令y1=y2则x^2-2x+3=3x-1整理得（x-1）(x-4)=0,于是x=1或x=4

令y1=y2 则
x^2-2x+3=3x-1
x^2-5x+4=0
所以 x为1或4的时候 y1于y2相等

Y1 = Y2
x^2 - 2x + 3 = 3x - 1
x^2 - 5x + 4 = 0
(x-4)(x-1) = 0
x = 4 or 1

y1=y2
x²-2x+3=3x-1
x²-5x+4=0
（x-1)(x-4)=0
x=1
或
x=4

y1=y2
即x²-2x+3=3x-1
所以x²-2x-3x+3+1=0
x²-5x+4=0
即（x-1）（x-4）=0
解得x=1或x=4
即x=1或x=4时，y1=y2