化简求值;{[(a-2)/(a^2+2a)]-[(a-1)/(a^2+4a+4)]}除以(a-4)/(a+2),其中a满足a^2+2a-1=0应该能看懂吧
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![化简求值;{[(a-2)/(a^2+2a)]-[(a-1)/(a^2+4a+4)]}除以(a-4)/(a+2),其中a满足a^2+2a-1=0应该能看懂吧](/uploads/image/z/113150-38-0.jpg?t=%E5%8C%96%E7%AE%80%E6%B1%82%E5%80%BC%EF%BC%9B%7B%5B%28a-2%29%2F%28a%5E2%2B2a%29%5D-%5B%28a-1%29%2F%28a%5E2%2B4a%2B4%29%5D%7D%E9%99%A4%E4%BB%A5%28a-4%29%2F%28a%2B2%29%2C%E5%85%B6%E4%B8%ADa%E6%BB%A1%E8%B6%B3a%5E2%2B2a-1%3D0%E5%BA%94%E8%AF%A5%E8%83%BD%E7%9C%8B%E6%87%82%E5%90%A7)
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化简求值;{[(a-2)/(a^2+2a)]-[(a-1)/(a^2+4a+4)]}除以(a-4)/(a+2),其中a满足a^2+2a-1=0应该能看懂吧
化简求值;{[(a-2)/(a^2+2a)]-[(a-1)/(a^2+4a+4)]}除以(a-4)/(a+2),其中a满足a^2+2a-1=0
应该能看懂吧
化简求值;{[(a-2)/(a^2+2a)]-[(a-1)/(a^2+4a+4)]}除以(a-4)/(a+2),其中a满足a^2+2a-1=0应该能看懂吧
{[(a-2)/(a^2+2a)]-[(a-1)/(a^2+4a+4)]}除以(a-4)/(a+2)
={[(a-2)/a(a+2)]-[(a-1)/(a+2)²]}除以(a-4)/(a+2)
=[(a+2)(a-2)-a(a-1)]/a(a+2)²×(a+2)/(a-4)
=1/(a²+2a)
=1
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