已知log5(√6+1）+log2(√2-1）=a,则log5(√6-1）+log2(√2+1）=

已知log5(√6+1）+log2(√2-1）=a,则log5(√6-1）+log2(√2+1）= log5(1+√6)+log2(-1+√2)=a.则log5(-1+√6)+log2(1+√2)=?√=根号. 已知log5(根号6+1)+log2(根号2-1)=a,则log5(根号6-1)+log2(根号2+1)= （1）2log5*10+log5*0.25(2)log2(log2*16)(3)lg12.5-lg5/8+lg0.5第三题：y=√（x²+3x+2）+log2*3x的定义域是? 求下列各式的值 1）log2 6+log2 3 2)lg5+lg2 3)log5 3+log5 三分之一 4）log3 5-log3 15 比较1/log5(19)+2/log3(19)+3/log2(19) 和 1/log2（派）+2/log5（派）大小 (log2) ^2 - log5 *log20课本上 等于 （log2）^2 +(1+log2)(1-log2) = 1;（log2）^2 +(1+log2)(1-log2) 是怎么来的? 1、计算log5^35+2log1/2^根号2-log5^1/50-log5^14 2、已知log3^7=a,log2^3=b,求log21^28 lg(1/4)-lg2(5) 2log5(10)+log5(0.25) 2log2(25)-3log2(64) log2(log2(16) ) (log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(3-√5))=? 数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(3-√5)) 数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√(3-√5)) 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15 log的一道数学题log3 1/64×log4 √5×log1/25 27 √5是根号下5 ×是乘号=log3 2^(-6) ×log2^2 5^(1/2) ×log5^(-2) 3^3=[(-6)×log3 2] ×[(1/2)×(1/2)×log2 5] ×[(-1/2)×3×log5 3]这个是怎么转换的 底数也能放前面吗比如log2^ log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log2(32)-log2(3÷4）+log2log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2【log2(32)-log2(3÷4）+log2（6）】=?lgx+lg（x+15）=2 ..X 已知log2=a,log3=b,用a、b表示log5 72 (急~）1.已知log2=a,log3=b,用a、b表示log5 722.已知x=log2 5,求2^x+4^-x 怎样计算（log2)^2+(log5)^2+(2*log2)*log5 计算Log5 35+2log1/2√2-log5 1/50-log5 14急急急！！！