如图,点D在三角形ABC的边BC上,过点D坐DF平行于AB,交AC于点E连结BF,已知BD:DC=1:2,DE:EF=1:3,则S△ABC:S三角形BDF等于
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![如图,点D在三角形ABC的边BC上,过点D坐DF平行于AB,交AC于点E连结BF,已知BD:DC=1:2,DE:EF=1:3,则S△ABC:S三角形BDF等于](/uploads/image/z/1132718-14-8.jpg?t=%E5%A6%82%E5%9B%BE%2C%E7%82%B9D%E5%9C%A8%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E8%BE%B9BC%E4%B8%8A%2C%E8%BF%87%E7%82%B9D%E5%9D%90DF%E5%B9%B3%E8%A1%8C%E4%BA%8EAB%2C%E4%BA%A4AC%E4%BA%8E%E7%82%B9E%E8%BF%9E%E7%BB%93BF%2C%E5%B7%B2%E7%9F%A5BD%3ADC%3D1%3A2%2CDE%3AEF%3D1%3A3%2C%E5%88%99S%E2%96%B3ABC%3AS%E4%B8%89%E8%A7%92%E5%BD%A2BDF%E7%AD%89%E4%BA%8E)
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