已知│ab-2│+│a-1│=0,求1÷ab+1÷(a+1)(b+1)+1÷(a+2)(b+2)+…+1÷(a+2011)+(b+2011)的值

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已知│ab-2│+│a-1│=0,求1÷ab+1÷(a+1)(b+1)+1÷(a+2)(b+2)+…+1÷(a+2011)+(b+2011)的值
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已知│ab-2│+│a-1│=0,求1÷ab+1÷(a+1)(b+1)+1÷(a+2)(b+2)+…+1÷(a+2011)+(b+2011)的值
已知│ab-2│+│a-1│=0,求1÷ab+1÷(a+1)(b+1)+1÷(a+2)(b+2)+…+1÷(a+2011)+(b+2011)的值

已知│ab-2│+│a-1│=0,求1÷ab+1÷(a+1)(b+1)+1÷(a+2)(b+2)+…+1÷(a+2011)+(b+2011)的值
ab=2,a=1
所以b=2
所以原式等于1/3+1/5+1/7.1/(2012*2013)