已知x-y=1,求代数式1/2(x²+y²)-xy
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已知x-y=1,求代数式1/2(x²+y²)-xy
已知x-y=1,求代数式1/2(x²+y²)-xy
已知x-y=1,求代数式1/2(x²+y²)-xy
1/2(x²+y²)-xy
=1/2(x²+y²-2xy)+xy-xy
=1/2(x-y)²
=1/2
1/2(x²+y²)-xy
=1/2(x²+y²-2xy)
=1/2(x-y)²
=1/2