已知3a-b/3=2a+c/5=2b+c/7,则a:b:c=
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已知3a-b/3=2a+c/5=2b+c/7,则a:b:c=
已知3a-b/3=2a+c/5=2b+c/7,则a:b:c=
已知3a-b/3=2a+c/5=2b+c/7,则a:b:c=
a:b:c=11:12:35
解法:令3a-b/3=2a+c/5=2b+c/7=k,然后用k表示出a,b,c.
设3a-b/3=2a+c/5=2b+c/7=k则3a-b=3k (1) 2a+c=5k (2) 2b+c=7k (3)(3)-(2)=2b+c-2a-c=2b-2a=7k-5k=2k b-a=k 3a-b=3k 所以a=2k,b=3k 因为2b+c=7k 所以c=k则a:b:c=2k:3k:k=2:3:1