圆的方程为:(x+3)^2+(y-4)^2=4;直线y=mx与圆相交与两点P和Q,O为坐标原点,求OP向量与OQ向量的点积的值?
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![圆的方程为:(x+3)^2+(y-4)^2=4;直线y=mx与圆相交与两点P和Q,O为坐标原点,求OP向量与OQ向量的点积的值?](/uploads/image/z/11451627-27-7.jpg?t=%E5%9C%86%E7%9A%84%E6%96%B9%E7%A8%8B%E4%B8%BA%EF%BC%9A%28x%2B3%29%5E2%2B%28y-4%29%5E2%3D4%3B%E7%9B%B4%E7%BA%BFy%3Dmx%E4%B8%8E%E5%9C%86%E7%9B%B8%E4%BA%A4%E4%B8%8E%E4%B8%A4%E7%82%B9P%E5%92%8CQ%2CO%E4%B8%BA%E5%9D%90%E6%A0%87%E5%8E%9F%E7%82%B9%2C%E6%B1%82OP%E5%90%91%E9%87%8F%E4%B8%8EOQ%E5%90%91%E9%87%8F%E7%9A%84%E7%82%B9%E7%A7%AF%E7%9A%84%E5%80%BC%3F)
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