1.2^2+4^2+6^2+……(2n)^2=2/3*n(n+1)(2n+1)2.是否存在常数a,b,c,使得等式1*2^2+2*3^2+……+n(n+1)^2=n(n+1)/12*(an^2+bn+c)对一切正整数n都成立?
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1.2^2+4^2+6^2+……(2n)^2=2/3*n(n+1)(2n+1)2.是否存在常数a,b,c,使得等式1*2^2+2*3^2+……+n(n+1)^2=n(n+1)/12*(an^2+bn+c)对一切正整数n都成立?
1.
2^2+4^2+6^2+……(2n)^2=2/3*n(n+1)(2n+1)
2.
是否存在常数a,b,c,使得等式
1*2^2+2*3^2+……+n(n+1)^2=n(n+1)/12*(an^2+bn+c)
对一切正整数n都成立?
1.2^2+4^2+6^2+……(2n)^2=2/3*n(n+1)(2n+1)2.是否存在常数a,b,c,使得等式1*2^2+2*3^2+……+n(n+1)^2=n(n+1)/12*(an^2+bn+c)对一切正整数n都成立?
2、a=3,b=11,c=10
an=n^3+2n^2+n
1+2+3+……+n=n(n+1)/2
1^2+2^2+3^2+……+n^2=n(n+1)(2n+1)/6
1^3+2^3+3^3+……+n^3=n^2(n+1)^2/4
将这几个公式代入就可以求Sn了.
分好高 题好简单
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