x#y=xy/1+(x+1)(y+a)/1 且2#1=12/7 求3#1值X#y=1/xy+1/(x+1)(y+A)

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x#y=xy/1+(x+1)(y+a)/1 且2#1=12/7 求3#1值X#y=1/xy+1/(x+1)(y+A)
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x#y=xy/1+(x+1)(y+a)/1 且2#1=12/7 求3#1值X#y=1/xy+1/(x+1)(y+A)
x#y=xy/1+(x+1)(y+a)/1 且2#1=12/7 求3#1值
X#y=1/xy+1/(x+1)(y+A)

x#y=xy/1+(x+1)(y+a)/1 且2#1=12/7 求3#1值X#y=1/xy+1/(x+1)(y+A)
x=2,y=1
2#1=1/2+1/(2+1)(1+a)=7/12
1/3(1+a)=1/12
1+a=4
a=3
3#1=1/3+1/(3+1)(1+3)
=1/3+1/16
=19/48