已知三角形ABC顶点B(-1,-3),C(3,5)若A在抛物线y=x∧2-4上移动,求三角形ABC的重心的轨迹方程?若设G为(x,y)A为(m,n)那么x=(-1+3+m)\3,y=(-3+5+n)\3怎么理解
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![已知三角形ABC顶点B(-1,-3),C(3,5)若A在抛物线y=x∧2-4上移动,求三角形ABC的重心的轨迹方程?若设G为(x,y)A为(m,n)那么x=(-1+3+m)\3,y=(-3+5+n)\3怎么理解](/uploads/image/z/11468807-71-7.jpg?t=%E5%B7%B2%E7%9F%A5%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E9%A1%B6%E7%82%B9B%EF%BC%88-1%2C-3%EF%BC%89%2CC%EF%BC%883%2C5%EF%BC%89%E8%8B%A5A%E5%9C%A8%E6%8A%9B%E7%89%A9%E7%BA%BFy%EF%BC%9Dx%E2%88%A72-4%E4%B8%8A%E7%A7%BB%E5%8A%A8%2C%E6%B1%82%E4%B8%89%E8%A7%92%E5%BD%A2ABC%E7%9A%84%E9%87%8D%E5%BF%83%E7%9A%84%E8%BD%A8%E8%BF%B9%E6%96%B9%E7%A8%8B%3F%E8%8B%A5%E8%AE%BEG%E4%B8%BA%EF%BC%88x%2Cy%EF%BC%89A%E4%B8%BA%EF%BC%88m%2Cn%EF%BC%89%E9%82%A3%E4%B9%88x%3D%EF%BC%88-1%2B3%2Bm%EF%BC%89%5C3%2Cy%3D%EF%BC%88-3%2B5%2Bn%EF%BC%89%5C3%E6%80%8E%E4%B9%88%E7%90%86%E8%A7%A3)
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