已知二次函数f(x)=x²-16x+q+3 (1)当q=1时,求f(x)在[-1,1]上的最值(1)当q=1时,求f(x)在[-1,1]上的最值 (2)问:是否存在常数q(0
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![已知二次函数f(x)=x²-16x+q+3 (1)当q=1时,求f(x)在[-1,1]上的最值(1)当q=1时,求f(x)在[-1,1]上的最值 (2)问:是否存在常数q(0](/uploads/image/z/11470800-48-0.jpg?t=%E5%B7%B2%E7%9F%A5%E4%BA%8C%E6%AC%A1%E5%87%BD%E6%95%B0f%EF%BC%88x%EF%BC%89%3Dx%26%23178%3B-16x%2Bq%2B3+%EF%BC%881%EF%BC%89%E5%BD%93q%3D1%E6%97%B6%2C%E6%B1%82f%28x%29%E5%9C%A8%5B-1%2C1%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%80%BC%EF%BC%881%EF%BC%89%E5%BD%93q%3D1%E6%97%B6%2C%E6%B1%82f%28x%29%E5%9C%A8%5B-1%2C1%5D%E4%B8%8A%E7%9A%84%E6%9C%80%E5%80%BC+%282%29%E9%97%AE%EF%BC%9A%E6%98%AF%E5%90%A6%E5%AD%98%E5%9C%A8%E5%B8%B8%E6%95%B0q%EF%BC%880)
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已知二次函数f(x)=x²-16x+q+3 (1)当q=1时,求f(x)在[-1,1]上的最值(1)当q=1时,求f(x)在[-1,1]上的最值 (2)问:是否存在常数q(0
已知二次函数f(x)=x²-16x+q+3 (1)当q=1时,求f(x)在[-1,1]上的最值
(1)当q=1时,求f(x)在[-1,1]上的最值 (2)问:是否存在常数q(0
已知二次函数f(x)=x²-16x+q+3 (1)当q=1时,求f(x)在[-1,1]上的最值(1)当q=1时,求f(x)在[-1,1]上的最值 (2)问:是否存在常数q(0