求值 (1)tan11π/12 (2) tan285
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求值 (1)tan11π/12 (2) tan285
求值 (1)tan11π/12 (2) tan285
求值 (1)tan11π/12 (2) tan285
tan11/π12=tan(π/2+5π/12)=-tan5π/12=-4/3
tan285=tan(3π/2+15)=-tan15=-3/4
(1)tan11π/12=-0.26794919243112270647255365849413......
(2)a: tan 285 =-1.2218847654241467831152614828998......
b: tan 285° =-3.7320508075688772935274463415059......