求极限
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求极限
求极限
求极限
1)原式=lim (x-1)(x+1)/(2x+1)(x-1)=lim(x+1)/(2x+1)=2/3
2)原式=lim (2+3/x)/(6-1/x)=2/6=1/3
3)原式=lim x^2[1+√(1+x^2)]/[1-(1+x^2)]=lim -[1+√(1+x^2)]=-2
4)原式=lim[(x^2+1)-(x^2-1)]/[√(x^2+1)+√(x^2-1)]=lim 2/[√(x^2+1)+√(x^2-1)]=0
(1)lim(x-1)(x+1)/(2x+1)(x-1)=lim(=2/3; (2)lim(2x+3)/x/(6x-1)/x=lim(2+3/x)/(6-1/x)==1/3;