x^2n+x^n-1/9y^2+1/4因式分解?我想了半天了
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/27 06:15:41
![x^2n+x^n-1/9y^2+1/4因式分解?我想了半天了](/uploads/image/z/11483409-57-9.jpg?t=x%5E2n%2Bx%5En-1%2F9y%5E2%2B1%2F4%E5%9B%A0%E5%BC%8F%E5%88%86%E8%A7%A3%3F%E6%88%91%E6%83%B3%E4%BA%86%E5%8D%8A%E5%A4%A9%E4%BA%86)
x͒0_%cb 1
>4[.,HDE.Ip+>_juP'qp|'|It'FE^b".E;5ʓn+?8i=v:?@R&b__;ÜB {^
=j,
s^+WK0G~iN*I;FFM5rG5 h3pU,XVapx5؋r2;[=^f(~6
x^2n+x^n-1/9y^2+1/4因式分解?我想了半天了
x^2n+x^n-1/9y^2+1/4因式分解?我想了半天了
x^2n+x^n-1/9y^2+1/4因式分解?我想了半天了
x^2n+x^n-1/9y^2+1/4
=(x^n)^2+(x^n)+1/4-(1/9)y^2
=[(x^n)^2+(x^n)+1/4]-(1/9)y^2
=[x^n+1/2]^2-[(1/3)y]^2
=[x^n+1/2+(1/3)y]*[x^n+1/2-(1/3)y]
(1)-18m^4 9m^2n^2 5n^4 =-(18m^4-9m^2n^2-5n^4) =-(3m^2 n^2)(6m^2-5n^2) (2)x^4-10x^2y^2 9y^4 =(x^2-y^2)(x^2
x^2n+x^n-1/9y^2+1/4
=(x^n)^2+(x^n)+1/4-(1/9)y^2
=[(x^n)^2+(x^n)+1/4]-(1/9)y^2
=[x^n+1/2]^2-[(1/3)y]^2
=[x^n+1/2+(1/3)y]*[x^n+1/2-(1/3)y]
只能分到这了
分解因式 x^n+2 *y^n-2+x^n+1* y^n-1+x^n+1* y^n-1
因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2)
因式分解4x^n+2-9x^n+6x^n-1-x^n-2
-2(x-y)^2n-4(y-x)^2n+1 (n为正整数)因式分解
分解因式-2x^(5n-1)y^n+4x^(3n-1)y^(n+2)-2x^(n-1)y^(n+4)
分解因式:-2X^(5n+1)Y^n+4X^(3n+1)Y^(n+2)-2X^(n+1)Y^(n+4)
诺M+4的绝对值与N的平方-2N+1互为相反数,把多项试x的平方+4Y平方-MXY-N分解因试
x^n(y^2n-1)/x^n-1(y^n+1)
x^n(y^2n-1)/x^n-1(y^n+1)
因式分解(公式法)4(x+2y)^2-9(x-y)^2x^(n+3)-x^(n-1)
x^n+x^n-1y+x^n-2y^2+.+x^2y^n-2 +xy^n-1 +y^n=多少?
单项式除以单项式 -x^n-2y^n+1÷(-4x^n-4y^n-3)
f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n
x^2n+x^n-1/9y^2+1/4因式分解?我想了半天了
设随机变量X~N(-1 4),N(-2 9) ,且XY相互独立,则x-y~( )
4x^n+2-9x^n+6x^n-1-x^n-24x^(n+2)-9x^n+6x^(n-1)-x^(n-2),n是整数且大于2
用列举法表示 集合{x|x=(-1)^n,n∈N}{y|y=-x^2+6,x∈N,y∈N}{(x,y)|y=-x^2+6,x∈N,y∈N}
(8x^n+1-3x^n-1)-2(-x+9x^n+1-4x^n)=