会哪题就解哪题,好的追加50-100,如图,在△ABC中,点D,E分别在边AB,BC上,且S△BDE=S四边形ADEC,分别过点D,E作DF∥BC,EG∥AB交AC于点F,G.(1)如果分别延长DF,EG交于点M,求证:S△FGM=S△ADF+S△CEG(2)试判
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![会哪题就解哪题,好的追加50-100,如图,在△ABC中,点D,E分别在边AB,BC上,且S△BDE=S四边形ADEC,分别过点D,E作DF∥BC,EG∥AB交AC于点F,G.(1)如果分别延长DF,EG交于点M,求证:S△FGM=S△ADF+S△CEG(2)试判](/uploads/image/z/11485170-18-0.jpg?t=%E4%BC%9A%E5%93%AA%E9%A2%98%E5%B0%B1%E8%A7%A3%E5%93%AA%E9%A2%98%2C%E5%A5%BD%E7%9A%84%E8%BF%BD%E5%8A%A050-100%2C%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2C%E7%82%B9D%2CE%E5%88%86%E5%88%AB%E5%9C%A8%E8%BE%B9AB%2CBC%E4%B8%8A%2C%E4%B8%94S%E2%96%B3BDE%3DS%E5%9B%9B%E8%BE%B9%E5%BD%A2ADEC%2C%E5%88%86%E5%88%AB%E8%BF%87%E7%82%B9D%2CE%E4%BD%9CDF%E2%88%A5BC%2CEG%E2%88%A5AB%E4%BA%A4AC%E4%BA%8E%E7%82%B9F%2CG.%EF%BC%881%EF%BC%89%E5%A6%82%E6%9E%9C%E5%88%86%E5%88%AB%E5%BB%B6%E9%95%BFDF%2CEG%E4%BA%A4%E4%BA%8E%E7%82%B9M%2C%E6%B1%82%E8%AF%81%EF%BC%9AS%E2%96%B3FGM%3DS%E2%96%B3ADF%2BS%E2%96%B3CEG%EF%BC%882%EF%BC%89%E8%AF%95%E5%88%A4)
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