f(x)=2cos(kx/4+π/6)-3的最小正周期不大于2,求k最小正整数解还有:1.若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)的值那个题目(kx/4+π/6)是kx除以4的商 乘以 π除以6的商
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![f(x)=2cos(kx/4+π/6)-3的最小正周期不大于2,求k最小正整数解还有:1.若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)的值那个题目(kx/4+π/6)是kx除以4的商 乘以 π除以6的商](/uploads/image/z/11491511-23-1.jpg?t=f%28x%29%3D2cos%28kx%2F4%2B%CF%80%2F6%29-3%E7%9A%84%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E4%B8%8D%E5%A4%A7%E4%BA%8E2%2C%E6%B1%82k%E6%9C%80%E5%B0%8F%E6%AD%A3%E6%95%B4%E6%95%B0%E8%A7%A3%E8%BF%98%E6%9C%89%EF%BC%9A1.%E8%8B%A5%E5%87%BD%E6%95%B0f%28x%29%E6%98%AF%E4%BB%A5%CF%80%2F2%E4%B8%BA%E6%9C%80%E5%B0%8F%E6%AD%A3%E5%91%A8%E6%9C%9F%E7%9A%84%E5%87%BD%E6%95%B0%2C%E4%B8%94f%28%CF%80%2F3%29%3D1%2C%E6%B1%82f%2817%CF%80%2F6%29%E7%9A%84%E5%80%BC%E9%82%A3%E4%B8%AA%E9%A2%98%E7%9B%AE%28kx%2F4%2B%CF%80%2F6%29%E6%98%AFkx%E9%99%A4%E4%BB%A54%E7%9A%84%E5%95%86+%E4%B9%98%E4%BB%A5+%CF%80%E9%99%A4%E4%BB%A56%E7%9A%84%E5%95%86)
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f(x)=2cos(kx/4+π/6)-3的最小正周期不大于2,求k最小正整数解还有:1.若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)的值那个题目(kx/4+π/6)是kx除以4的商 乘以 π除以6的商
f(x)=2cos(kx/4+π/6)-3的最小正周期不大于2,求k最小正整数解
还有:
1.若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)的值
那个题目(kx/4+π/6)是kx除以4的商 乘以 π除以6的商
f(x)=2cos(kx/4+π/6)-3的最小正周期不大于2,求k最小正整数解还有:1.若函数f(x)是以π/2为最小正周期的函数,且f(π/3)=1,求f(17π/6)的值那个题目(kx/4+π/6)是kx除以4的商 乘以 π除以6的商
T=2π/|k|=π
k>=π
最小正整数 k=4
f(17π/6)=f(3π-π/6)=f(-π/6)=f(-π/2+π/3)
=f(π/3)=1