sin(x+π/6)=-√2/2,x属于-π/6,11π/6,求x

若x属于(0,π/2),且6 cosx=5 tan X,则sin X 求下列函数周期 y=3sin(x/4) x属于Ry=2sin(2x-π/6) y=2sin(x/2+π/6),x属于R y=-6sin(2x-π/3）,x属于R 写出振幅,周期,初相 sin(x+π/6)=-√2/2,x属于-π/6,11π/6,求x y=sin(2x+π/6),x属于[π/6,3π/4],求值域 y=2sin[(π/6)-2x]的单调递增区间 x属于[0,π] 函数y=sin（x+π/6）,x属于【0,π/2】的值域是? 已知sin x=15/17,x属于π/2,π,求tan(π/4+x) 1.y=sin(1/2x+π/6),x属于[0,π/3] 2.y=-cos(3x-π/3),x属于[-π/3,π/3] x属于(pai/4,pai),sin(x+pai/4)=√2/3,sin(x-pai/4)= f(x)=2sin(2x+π/6) x属于[π/12,π/2] 求值域 f(x)=2sin(2x-π/6) 若x属于【0,π】 求y的单调增区间 函数y=2sin((π/3)-x)-cos((π/6)+x) (x属于R）的最小值是 当x属于[0,π/2]时,求函数f(x)=sin(π/6-x)-cosx的值域 求下列函数的奇偶性f(x)=(1+sin x-cos x)/(1+cos x+sin x),x属于[(-π/2),(π/2)] 已知sin（π/4+x）sin（π/4-x）=1/6,x属于（π/2,π）,求sin4x的值 已知函数f（x）=［2sin（x-π/6）+√3sin x］cos x+sin^2x,x∈R 已知函数y=2sin(3x+π/3),x属于R当x属于[-2π/9,π/6]时,求函数的最大值与最小值