(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?

来源:学生作业帮助网 编辑:作业帮 时间:2024/07/08 22:00:51
(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?
xՒJ@_Jm'34uϡd&6T@BQZѷ1|E+qs{rQLi&ӸD`RĄBCX8.NS%M5K#՟xNfuY3ގ}NI&b `0 Azvʚyv}c|C΄O!ay>K<ߵJqc.(j(B, R`|#w\-

(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?
(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)
(1)能否充分说明题干,(2)呢?

(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?
如果是解方程,应该有4个解.