(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/30 15:12:35
xՒJ@_Jm'34uϡd&6T@BQZѷ1|E+qs{rQLi&ӸD`RĄBCX8.NS%M5K#՟xNfuY3ގ}NI&b
`0 Azvʚyv}c| C΄O!ay>K<ߵJqc.(j(B,R`|#w\-
(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?
(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)
(1)能否充分说明题干,(2)呢?
(x^4-33x^2-40x+244)/(x^2-8x+15)=5成立,则(1)x=根号下(19-8根号下3)(2)x=根号下(19+8根号下3)(1)能否充分说明题干,(2)呢?
如果是解方程,应该有4个解.
*-----------------------------------------------*| 6 4 X | 8 X X | X X 5 || X X X | X X X | X 7 8 || X X X | X X X | X X X ||---------------+---------------+--------------- || X X X | X X X | 5 1 X || X X X | X 6 X | X X X || 8 X X | 3 5 X | 2 X X ||
(x/x-2-x/x+2)/4x/x-2
1/(1-x)+1/(1+x)+2/(1+x*x)+4/(1+x*x*x*x)+8/(1-x*x*x*x*x*x*x*x)怎么做
X(X-4)^2
|-x+2|+|4+x|
x^4-x^2
(x^2-4)x
x+2/x+1-x+3/x+2-x+4/x+3+x+5/x+4
通分x+4/x*x+4x与x-5/x(x-5)-2(x-5)
(x+3x+5x...+2009x)-(2x+4x+6x+...+2010x)
x{x+1}{x-1}}x-2}{x-3}-40
求一个数独答案X X X 9 X X X 8 2 X 6 3 X X 1 4 X 99 X 8 X X X X X XX X X 6 7 X 3 X XX 4 6 X 5 X 2 9 XX X 7 X 2 3 X X XX X X X X X 7 X 17 X 4 3 X X 6 2 X6 3 X X X 7 X X X
x(x+2)(x-2)-4x^2+8x
x^5-x^4+x^3-x^2+x-1
x^6-x^5+x^4-x^2+x-1
一个“整式的乘法”的问题请先阅读下列解题过程,再仿做下面的问题.已知X*X + X - 1=0,求X*X*X + 2*X*X + 3的值.解X*X*X + 2X*X +3=X*X*X +X*X -X +X*X +X +3=X{X*X +X -1} +X*X +X -1 +4=0+0+4=4+ x + X*X + X*X*X=0.+ X*X + X*X*X
难倒爱因斯坦的九宫格X 7 X | X 8 1 | X X X |X X X | X 4 X | 7 5 9 |X X 5 | 7 X 9 | X 1 4 |5 X X | X X 8 | 3 9 X |3 9 6 | 4 X 7 | X X 2 |X 8 7 | 9 X X | X X X |4 X X | 6 X 5 | X X X | X X 4 | X X 1 |2 X X | X X X | X X X | X 3 X | X X X |X 6
x+2x+3x+4x+5x+6x+7x+8x+9x=9x-8x-7x-6x-5x-4x-3x-2x-x.x等于多少?