已知如图,在△ABC中,AB=AC.∠BAC=a,且60°<a<120°.P为△ABC内部一点,且PC=AC,∠PCA=120°-a(1)用含a的代数式表示∠BAP,得∠APC=(2)求证∠BAP=∠PCB(3)求∠PBC的度数
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![已知如图,在△ABC中,AB=AC.∠BAC=a,且60°<a<120°.P为△ABC内部一点,且PC=AC,∠PCA=120°-a(1)用含a的代数式表示∠BAP,得∠APC=(2)求证∠BAP=∠PCB(3)求∠PBC的度数](/uploads/image/z/11498454-54-4.jpg?t=%E5%B7%B2%E7%9F%A5%E5%A6%82%E5%9B%BE%2C%E5%9C%A8%E2%96%B3ABC%E4%B8%AD%2CAB%3DAC.%E2%88%A0BAC%3Da%2C%E4%B8%9460%C2%B0%EF%BC%9Ca%EF%BC%9C120%C2%B0.P%E4%B8%BA%E2%96%B3ABC%E5%86%85%E9%83%A8%E4%B8%80%E7%82%B9%2C%E4%B8%94PC%3DAC%2C%E2%88%A0PCA%3D120%C2%B0-a%281%29%E7%94%A8%E5%90%ABa%E7%9A%84%E4%BB%A3%E6%95%B0%E5%BC%8F%E8%A1%A8%E7%A4%BA%E2%88%A0BAP%2C%E5%BE%97%E2%88%A0APC%3D%282%29%E6%B1%82%E8%AF%81%E2%88%A0BAP%3D%E2%88%A0PCB%283%29%E6%B1%82%E2%88%A0PBC%E7%9A%84%E5%BA%A6%E6%95%B0)
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