y=(x^2-2*x+6)/(x-1) 的值域用不等式怎么求啊

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/30 09:47:51
y=(x^2-2*x+6)/(x-1) 的值域用不等式怎么求啊
x)ը35Ҫ6ר5Tx>iÞ?Ɏk;dgdzMOv$铩SΆ2[Ք -Mc!r`)УΥF:fB>suuԳ/.H̳̩P0KүxmlΧ+"0 WS';v=n`~OӎR0+5Au@FZ$kiZ"P

y=(x^2-2*x+6)/(x-1) 的值域用不等式怎么求啊
y=(x^2-2*x+6)/(x-1) 的值域用不等式怎么求啊

y=(x^2-2*x+6)/(x-1) 的值域用不等式怎么求啊
y=[(x-1)²+5]/(x-1)
=(x-1)+5/(x-1)
≥2√5
y∈[2√5,∞).

x 2^b/x》2(根号x*2^b/x)=2(根号2^b) 值域为【6， ..)则： 2根号2^b=6,根号2^b=3, 2^b=9,b=log(2)9

2(x+y)-3(x-y)=1 6(x+y)+(x-y)=51 {3(x+y)-4(x-y)=4 {x+y/2 + x-y/6=1 {6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1 求值域 1,y=(x+2)/(x*x+3x+6) 2,y=3x/(x*x+4) 若2x-3y+4=0则x（x*x-1)+x(5-x*x)-6y+7 x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2 1.(x-2y)(x+2y)-(x平方+y)(x平方-y) 2.(2x-y)(y+2x)-(2y+x)(2y-x)3.已知：x+y=6,x平方-y平方=48,求x,y的值4.x平方-2x分之x+2 -- x平方-4x+4分之x-1 (x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2 (x-2y)(x+y)-2x(-2x-3y)+6x(-x-y),其中x=-1,y=2要讲解和答题 已知：2x+y=6,x-3y=1 求7y(x-3y)(x-3y)-2(3y-x)(3y-x) y=(6x^2-4x+1)/x 【2(x-y)(x-y)(x-y)-8(x-y)(x-y)(x+y)+6y(x-y)(x-y)]/2(x-y)(x-y) 函数,y=3x/(x^2+x+1) ,x 函数y=3x/(x^2+x+1) （x 函数y=2x/x²-x+1（x xy²/(x²y-y) × x²/(x²+x)=(x²-3x)/(x²-5x) × 2x-10/(x²-6x+9)=化简求植x²-1/(x²-x-2)除以x/2x-4,其中x=1/2[x-x/(x+1)]除以[x/(2x-4)] ,其中x=√2+1 已知x+y=a,2x-y=-2a,求[（x/y-y/x)/(x+y)-x(1/x-1/y)]/[(x+1)/y]的值 若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值