①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
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①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^①若x2+4y2+2x-4y+2=0,求5x2=16y2的算术平方根.②已知y=√4-x+√x-4+2,求x^
题目不完整.
①配方
=(x^2+2x+1)+(4y^2-4y+1)
=(x+1)^2+(2y-1)^2=0
一个数的平方≥0 所以两个平方下的式子都=0
x+1=0 2y-1=0
解得x=-1 y=1/2
代入5x2-16y2=5*(-1)^2-16*(1/2)^2=1
②因为根号下的式子≥0
所以4-x≥0 x-4≥0
4≤x≤4 所以x=4
所以x^2=16