1、设方程x²-3x+2=0的两个根分别是α,β,求log5 (α-β)²/α²+β²的值2、设f(x)是一次函数,且f(1)=1,f(x+1)=f(x)+3,求f(x)的解析式3、已知f(x)=cos²x-sinx+1,求该函数的最大值和最小值4、
来源:学生作业帮助网 编辑:作业帮 时间:2024/08/15 17:24:37
![1、设方程x²-3x+2=0的两个根分别是α,β,求log5 (α-β)²/α²+β²的值2、设f(x)是一次函数,且f(1)=1,f(x+1)=f(x)+3,求f(x)的解析式3、已知f(x)=cos²x-sinx+1,求该函数的最大值和最小值4、](/uploads/image/z/11511148-4-8.jpg?t=1%E3%80%81%E8%AE%BE%E6%96%B9%E7%A8%8Bx%26%23178%3B-3x%2B2%3D0%E7%9A%84%E4%B8%A4%E4%B8%AA%E6%A0%B9%E5%88%86%E5%88%AB%E6%98%AF%CE%B1%2C%CE%B2%2C%E6%B1%82log5+%28%CE%B1-%CE%B2%EF%BC%89%26%23178%3B%EF%BC%8F%CE%B1%26%23178%3B%2B%CE%B2%26%23178%3B%E7%9A%84%E5%80%BC2%E3%80%81%E8%AE%BEf%28x%29%E6%98%AF%E4%B8%80%E6%AC%A1%E5%87%BD%E6%95%B0%2C%E4%B8%94f%281%29%3D1%2Cf%28x%2B1%29%3Df%28x%29%2B3%2C%E6%B1%82f%28x%29%E7%9A%84%E8%A7%A3%E6%9E%90%E5%BC%8F3%E3%80%81%E5%B7%B2%E7%9F%A5f%EF%BC%88x%EF%BC%89%3Dcos%26%23178%3Bx-sinx%2B1%2C%E6%B1%82%E8%AF%A5%E5%87%BD%E6%95%B0%E7%9A%84%E6%9C%80%E5%A4%A7%E5%80%BC%E5%92%8C%E6%9C%80%E5%B0%8F%E5%80%BC4%E3%80%81)
xTNQ~4i0B6`FMb TK@ՊDP-ƶ
x,\
ٳMibz37͜OҙAouGJH4tvlfǼeF_vߑ'2~6;JddD;' 4AS biu9۲mn&|Ue8KR9Ђ
q#Ё>[