已知函数ƒ(x)=x²-ax+㏑x+b(a,b∈R)(1)若函数ƒ(x)在x=1处的切线方程为x+y+2=0,求实数a,b的值(2)若ƒ(x)在其定义域内单调递增,求a的取值范围
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![已知函数ƒ(x)=x²-ax+㏑x+b(a,b∈R)(1)若函数ƒ(x)在x=1处的切线方程为x+y+2=0,求实数a,b的值(2)若ƒ(x)在其定义域内单调递增,求a的取值范围](/uploads/image/z/11533655-47-5.jpg?t=%E5%B7%B2%E7%9F%A5%E5%87%BD%E6%95%B0%26%23402%3B%EF%BC%88x%EF%BC%89%3Dx%26%23178%3B-ax%2B%E3%8F%91x%2Bb%28a%2Cb%E2%88%88R%29%EF%BC%881%EF%BC%89%E8%8B%A5%E5%87%BD%E6%95%B0%26%23402%3B%EF%BC%88x%EF%BC%89%E5%9C%A8x%3D1%E5%A4%84%E7%9A%84%E5%88%87%E7%BA%BF%E6%96%B9%E7%A8%8B%E4%B8%BAx%2By%2B2%3D0%2C%E6%B1%82%E5%AE%9E%E6%95%B0a%2Cb%E7%9A%84%E5%80%BC%EF%BC%882%EF%BC%89%E8%8B%A5%26%23402%3B%EF%BC%88x%EF%BC%89%E5%9C%A8%E5%85%B6%E5%AE%9A%E4%B9%89%E5%9F%9F%E5%86%85%E5%8D%95%E8%B0%83%E9%80%92%E5%A2%9E%2C%E6%B1%82a%E7%9A%84%E5%8F%96%E5%80%BC%E8%8C%83%E5%9B%B4)
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