2011自主招生华约压轴.设Pn表示连续抛n次硬币,不出现连续三次正面的概率.1)求P1,P2,P3,P42)求Pn的递推和通项3)求Pn的极限并阐述其实际意义P1=P2=1,P3=7/8,P4=13/16递推式算出来Pn+1=Pn-1/16Pn-3.很奇怪然
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![2011自主招生华约压轴.设Pn表示连续抛n次硬币,不出现连续三次正面的概率.1)求P1,P2,P3,P42)求Pn的递推和通项3)求Pn的极限并阐述其实际意义P1=P2=1,P3=7/8,P4=13/16递推式算出来Pn+1=Pn-1/16Pn-3.很奇怪然](/uploads/image/z/11539371-3-1.jpg?t=2011%E8%87%AA%E4%B8%BB%E6%8B%9B%E7%94%9F%E5%8D%8E%E7%BA%A6%E5%8E%8B%E8%BD%B4.%E8%AE%BEPn%E8%A1%A8%E7%A4%BA%E8%BF%9E%E7%BB%AD%E6%8A%9Bn%E6%AC%A1%E7%A1%AC%E5%B8%81%2C%E4%B8%8D%E5%87%BA%E7%8E%B0%E8%BF%9E%E7%BB%AD%E4%B8%89%E6%AC%A1%E6%AD%A3%E9%9D%A2%E7%9A%84%E6%A6%82%E7%8E%87.1%29%E6%B1%82P1%2CP2%2CP3%2CP42%29%E6%B1%82Pn%E7%9A%84%E9%80%92%E6%8E%A8%E5%92%8C%E9%80%9A%E9%A1%B93%29%E6%B1%82Pn%E7%9A%84%E6%9E%81%E9%99%90%E5%B9%B6%E9%98%90%E8%BF%B0%E5%85%B6%E5%AE%9E%E9%99%85%E6%84%8F%E4%B9%89P1%3DP2%3D1%2CP3%3D7%2F8%2CP4%3D13%2F16%E9%80%92%E6%8E%A8%E5%BC%8F%E7%AE%97%E5%87%BA%E6%9D%A5Pn%2B1%3DPn-1%2F16Pn-3.%E5%BE%88%E5%A5%87%E6%80%AA%E7%84%B6)
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