如图,点B,F,C,E在一条直线上,FB=CE,AB//ED,AC//FD.求证AB=DE,AC=DF图片如下:11题啊file://C:\Documents and Settings\Administrator\Local Settings\Temporary Internet Files\Content.IE5\IFGXM18V\W020080505326796997009[1].jpg
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如图,点B,F,C,E在一条直线上,FB=CE,AB//ED,AC//FD.求证AB=DE,AC=DF图片如下:11题啊file://C:\Documents and Settings\Administrator\Local Settings\Temporary Internet Files\Content.IE5\IFGXM18V\W020080505326796997009[1].jpg
如图,点B,F,C,E在一条直线上,FB=CE,AB//ED,AC//FD.求证AB=DE,AC=DF
图片如下:11题啊
file://C:\Documents and Settings\Administrator\Local Settings\Temporary Internet Files\Content.IE5\IFGXM18V\W020080505326796997009[1].jpg
如图,点B,F,C,E在一条直线上,FB=CE,AB//ED,AC//FD.求证AB=DE,AC=DF图片如下:11题啊file://C:\Documents and Settings\Administrator\Local Settings\Temporary Internet Files\Content.IE5\IFGXM18V\W020080505326796997009[1].jpg
1.先说题外话:你给的图片地址在你自己C盘上,你又没有上传图片,所以别人是看不到的-_-!
2.证明如下:
因为:FB=CE,
所以:BC=EF;
因为:AB//ED,
所以:角ABC=角DEF;
又因为:AC//FD,
所以:角ACB=角DFE;
根据角边角对应相等的三角形全等,
所以AB=DE,AC=DF