设(x^2-x-1)^50=a100x^100+a99x^99+a98x^98+...+a0求a100+a99+a98+...+a1的值;求a100+a98+a96+...+a2+a0
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![设(x^2-x-1)^50=a100x^100+a99x^99+a98x^98+...+a0求a100+a99+a98+...+a1的值;求a100+a98+a96+...+a2+a0](/uploads/image/z/11556371-11-1.jpg?t=%E8%AE%BE%28x%5E2-x-1%29%5E50%3Da100x%5E100%2Ba99x%5E99%2Ba98x%5E98%2B...%2Ba0%E6%B1%82a100%2Ba99%2Ba98%2B...%2Ba1%E7%9A%84%E5%80%BC%3B%E6%B1%82a100%2Ba98%2Ba96%2B...%2Ba2%2Ba0)
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设(x^2-x-1)^50=a100x^100+a99x^99+a98x^98+...+a0求a100+a99+a98+...+a1的值;求a100+a98+a96+...+a2+a0
设(x^2-x-1)^50=a100x^100+a99x^99+a98x^98+...+a0求a100+a99+a98+...+a1的值;求a100+a98+a96+...+a2+a0
设(x^2-x-1)^50=a100x^100+a99x^99+a98x^98+...+a0求a100+a99+a98+...+a1的值;求a100+a98+a96+...+a2+a0
用迭代吧~递归也行~