3x+2y=1,2x-y+z=-4 x+zy-z=3过程...
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3x+2y=1,2x-y+z=-4 x+zy-z=3过程...
3x+2y=1,2x-y+z=-4 x+zy-z=3过程...
3x+2y=1,2x-y+z=-4 x+zy-z=3过程...
{3x+2y=1,①
{2x-y+z=-4 ②
{x+2y-z=3 ③
②+③得3x+y=-1 ④
①-④得y=2
把y=2代入④得3x+2=-1
x=-1
把x=-1,y=2代入②得-2-2+z=-4
z=0
所以原方程组的解是
{x=-1
{y=2
{z=0
(2x-y+z=-4)+(x+zy-z=3)=3x+zy=-1 (3x+2y=1)-(3x+zy=-1)=(2-z).y=2
本尊来打酱油来了
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