求y=2sin(-3x+派/4)的单调递减区间

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求y=2sin(-3x+派/4)的单调递减区间
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求y=2sin(-3x+派/4)的单调递减区间
求y=2sin(-3x+派/4)的单调递减区间

求y=2sin(-3x+派/4)的单调递减区间
y=-2sin(3x-π/4)
则y递减即sin递增
所以2kπ-π/2

y=-2sin(3x-π/4)
即求y=sin(3x-π/4)的增区间
令 2kπ-π/2 ≤3x-π/4≤2kπ+π/2
解得原函数的减区间是
[2kπ/3-π/12 ,2kπ/3+π/4](k∈Z)

由y=2sin(-3x+π/4)得y=-2sin(3x-π/4)
令2kπ-π/2 ≤3x-π/4≤2kπ+π/2得 2kπ/3-π/12 ≤x≤2kπ/3+π/4
故原函数的减区间为
[2kπ/3-π/12 ,2kπ/3+π/4](k∈Z)

[2kπ/3-π/12 ,2kπ/3+π/4](k∈Z)