求极限 ①lim x→n- (x-[x]) ②lim x→e log(x-1)/x-e ③limx→0+ log x^x①lim x→n- (x-[x]) n为任意自然数,[x]表示不大于X的最大整数②lim x→e log(x-1)/x-e ③limx→0+ log x^x②中, (log(x-1))/ x-e ,log的
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![求极限 ①lim x→n- (x-[x]) ②lim x→e log(x-1)/x-e ③limx→0+ log x^x①lim x→n- (x-[x]) n为任意自然数,[x]表示不大于X的最大整数②lim x→e log(x-1)/x-e ③limx→0+ log x^x②中, (log(x-1))/ x-e ,log的](/uploads/image/z/11562461-53-1.jpg?t=%E6%B1%82%E6%9E%81%E9%99%90+%E2%91%A0lim+x%E2%86%92n-+%EF%BC%88x-%5Bx%5D%EF%BC%89+%E2%91%A1lim+x%E2%86%92e+log%28x-1%29%2Fx-e+%E2%91%A2limx%E2%86%920%2B+log+x%5Ex%E2%91%A0lim+x%E2%86%92n-+%EF%BC%88x-%5Bx%5D%EF%BC%89+n%E4%B8%BA%E4%BB%BB%E6%84%8F%E8%87%AA%E7%84%B6%E6%95%B0%2C%5Bx%5D%E8%A1%A8%E7%A4%BA%E4%B8%8D%E5%A4%A7%E4%BA%8EX%E7%9A%84%E6%9C%80%E5%A4%A7%E6%95%B4%E6%95%B0%E2%91%A1lim+x%E2%86%92e+log%28x-1%29%2Fx-e+%E2%91%A2limx%E2%86%920%2B+log+x%5Ex%E2%91%A1%E4%B8%AD%EF%BC%8C+%EF%BC%88log%28x-1%29%EF%BC%89%2F+x-e++%EF%BC%8Clog%E7%9A%84)
求极限 ①lim x→n- (x-[x]) ②lim x→e log(x-1)/x-e ③limx→0+ log x^x①lim x→n- (x-[x]) n为任意自然数,[x]表示不大于X的最大整数②lim x→e log(x-1)/x-e ③limx→0+ log x^x②中, (log(x-1))/ x-e ,log的
求极限 ①lim x→n- (x-[x]) ②lim x→e log(x-1)/x-e ③limx→0+ log x^x
①lim x→n- (x-[x]) n为任意自然数,[x]表示不大于X的最大整数
②lim x→e log(x-1)/x-e
③limx→0+ log x^x
②中, (log(x-1))/ x-e ,log的真数为x-1
②③中,log 底数皆为e
求极限 ①lim x→n- (x-[x]) ②lim x→e log(x-1)/x-e ③limx→0+ log x^x①lim x→n- (x-[x]) n为任意自然数,[x]表示不大于X的最大整数②lim x→e log(x-1)/x-e ③limx→0+ log x^x②中, (log(x-1))/ x-e ,log的
①lim x→n- (x-[x])
=n-(n-1)
=1
②lim x→e ln(x-1)/(x-e)
=[lim x→e ln(x-1)*lim x→e [1/(x-e)]
=ln(e-1)*(+∞)
=+∞
③limx→0+ ln x^x
=limx→0+ (lnx)/(1/x)
=limx→0+ (1/x)/(-1/x²)
=limx→0+ (-x)
=0
求解过程见图片,第二个最后一个e如果在分母上组成x-e是无极限的,也就是无穷大
收起
①lim x→n- (x-[x])=n-(n-1)=1
②③不知谁为底数。