作业帮2x+π/3∈[π/3,+7π/6],所以sin（2x+π/3）∈[-1/2,1],为什么
来源：学生作业帮助网 编辑：作业帮 时间：2024/07/20 01:16:47
![2x+π/3∈[π/3,+7π/6],所以sin（2x+π/3）∈[-1/2,1],为什么](/uploads/image/z/11566514-2-4.jpg?t=2x%2B%CF%80%2F3%E2%88%88%5B%CF%80%2F3%2C%2B7%CF%80%2F6%5D%2C%E6%89%80%E4%BB%A5sin%EF%BC%882x%2B%CF%80%2F3%EF%BC%89%E2%88%88%5B-1%2F2%2C1%5D%2C%E4%B8%BA%E4%BB%80%E4%B9%88)
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2x+π/3∈[π/3,+7π/6],所以sin（2x+π/3）∈[-1/2,1],为什么
2x+π/3∈[π/3,+7π/6],所以sin（2x+π/3）∈[-1/2,1],为什么
2x+π/3∈[π/3,+7π/6],所以sin（2x+π/3）∈[-1/2,1],为什么
sin在[π/3,π/2]递增
在[π/2,7π/6]递减
所以最大sinπ/2=1
最小sin7π/6=-1/2