作业帮27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
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27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
27^1/3-1/2^log2(6)[6是真数在上面]-2lg1/4+4lg5
27^1/3-1/2^log₂6-2lg1/4+4lg5
=(3^3)^(1/3)-1/6-2lg2^(-2)+4lg5
=3-1/6-2*(-2)lg2+4lg5
=17/6+4(lg2+lg5)
=17/6+4lg10
=17/6+4
=41/6
a^(logab)=b
计算：（1）log2 (4^3*8^5);(2)log2 3+log2 6-log2 9
log2 6-log2 3
log2^6-log2^3
log2(3)×log2(4)=log2(7)?log2(3)×log2(4)=log2(7)吗?log2(1/49)+log2(1/16)+log2(1/27)等于多少呢?帮个忙!
log2^(4^7*2^5)+log2^6-log2^3
|[log2(x)]^2-3log2(x)+1|
log2 (x + 3) + log2(x + 2) = 1log2 (x + 3) + log2(x + 2) = 1
化简log2 1/2+log2 2/3+log2 3/4+.+log2 31/32
计算：log2(log2 32-log2 3/4+log2 6)
解方程log2(4^x+1)=x+log2(2^(x+3)-6)
解方程log2(x^2-3)=log2(6x-10)-1
已知方程X+X*log2 (6)+log2 (3)=0的两根为a,B求(1/4)^a * (1/4)^B的值韦达定理a+b=-log2(6)原式=(1/4)^(a+b)=(1/4)^[-log2(6)]=4^log2(6)=(2^2)^log2(6)=2^2log2(6)=2^log2(6)=36怎么从=2^log2(6)得出36的
[log2 1]+[log2 2]+[log2 3]+[log2 4]+[log2 5]+...+[log2 1024]=?[x]表示不超过x的最大整数2为底 答案是8204
计算(log3 2)(log2 6-1)
1/log2^6=log6^2?
log2(6)*log3(6)-[log2(3)+log3(2)]的值
(log2 6)×(log3 6)-(log2 3+log3 2)=
log2(6)*log3(6)-[log2(3)+log3(2)]的值