如果数列{an}满足a1=2,a2=1,且(an-1-an)/(anan-1)=(an-an+1)/(anan+1)(n≥2),则此数列的第10项为?
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如果数列{an}满足a1=2,a2=1,且(an-1-an)/(anan-1)=(an-an+1)/(anan+1)(n≥2),则此数列的第10项为?
如果数列{an}满足a1=2,a2=1,且(an-1-an)/(anan-1)=(an-an+1)/(anan+1)(n≥2),则此数列的第10项为?
如果数列{an}满足a1=2,a2=1,且(an-1-an)/(anan-1)=(an-an+1)/(anan+1)(n≥2),则此数列的第10项为?
(an-1-an)/(anan-1)=(an-an+1)/(anan+1),
然后化简得an=(2*an-1*an+1)/(an+1+an-1)
倒数倒一倒,得1/an=1/2(1/an+1+1/an-1)
化简得1/an- 1/an-1 =1/an+1-1/an
即{1/an-1/an-1}为等差数列,(n≥2).
然后可得d=1/2,1/a10=5,a10=1/5
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