请问由(2100x+700y)/(2100+700)=3% 且(900x+2700y)/(900+2700)=5%怎样推出x=2%,y=5%?
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请问由(2100x+700y)/(2100+700)=3% 且(900x+2700y)/(900+2700)=5%怎样推出x=2%,y=5%?
请问由(2100x+700y)/(2100+700)=3% 且(900x+2700y)/(900+2700)=5%怎样推出x=2%,y=5%?
请问由(2100x+700y)/(2100+700)=3% 且(900x+2700y)/(900+2700)=5%怎样推出x=2%,y=5%?
(2100x+700y)/(2100+700)=3%
(900x+2700y)/(900+2700)=5%
化简得525X+185Y=21①
5X+15Y=1②
联立①②得x=2%,y=5%
说句题外话,足下是不是被这个题的整齐性吓到了?就是二元一次方程嘛,还要闹那样?