函数数列{fn(x)}满足f1(1)/根号下(1+x^2) f(n+1)(x)=f1[fn(x)]求f2,f3并用数学归纳法证明fn解析式
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![函数数列{fn(x)}满足f1(1)/根号下(1+x^2) f(n+1)(x)=f1[fn(x)]求f2,f3并用数学归纳法证明fn解析式](/uploads/image/z/1158775-7-5.jpg?t=%E5%87%BD%E6%95%B0%E6%95%B0%E5%88%97%7Bfn%EF%BC%88x%EF%BC%89%7D%E6%BB%A1%E8%B6%B3f1%EF%BC%881%EF%BC%89%2F%E6%A0%B9%E5%8F%B7%E4%B8%8B%EF%BC%881%2Bx%5E2%29+f%28n%2B1%29%28x%29%3Df1%5Bfn%28x%29%5D%E6%B1%82f2%2Cf3%E5%B9%B6%E7%94%A8%E6%95%B0%E5%AD%A6%E5%BD%92%E7%BA%B3%E6%B3%95%E8%AF%81%E6%98%8Efn%E8%A7%A3%E6%9E%90%E5%BC%8F)
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