若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/17 23:57:39
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
x){ѽHBPXƦJ 5 tvf,6rjyڰ&H,}v6iUVhkTTjBE**<&M[2PMh Ph0 #V?A"ܶd=LTm6HlV&. F; K 16`γ/w\4ut2g }OvvW N\dUS

若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值

若2/x-1/y=3,求[y/x-y/x-y(x-y/x-x+y)]/x-2y/x的值
2/x-1/y=3
(2y-x)/(xy)=3
xy/(x-2y)=-1/3
{(y/x)-[y/(x-y)]*[(x-y)/x-x+y]}/[(x-2y)/x]
={y/x-[y/(x-y)*(x-y)/x]+[y/(x-y)*(x-y)]}*x/(x-2y)
=(y/x-y/x+y)*x/(x-2y)
=xy/(x-2y)
=-1/3

感觉题目有错,怎么有y/x-y/x呢