(x^2+y^2)/(x^2-xy+y^2)=2,求x/y

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(x^2+y^2)/(x^2-xy+y^2)=2,求x/y
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(x^2+y^2)/(x^2-xy+y^2)=2,求x/y
(x^2+y^2)/(x^2-xy+y^2)=2,求x/y

(x^2+y^2)/(x^2-xy+y^2)=2,求x/y

画图形,根据几何意义是求,图形上的点于原点的斜率

化简:x^2+y^2=2x^2-2xy+2y^2,即x^2-2xy+y^2=0,即(x-y)