sin(-π/7)和sin(-π/5)、cos4/7 π 、cos5/8 π 怎么算?如题!
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/25 05:04:06
x)+=ߠotR~Ok~Ob}s
Ύ?]rE"}J3OΆFsmt@BTE6i2F@M<;wo
sin(-π/7)和sin(-π/5)、cos4/7 π 、cos5/8 π 怎么算?如题!
sin(-π/7)和sin(-π/5)、cos4/7 π 、cos5/8 π 怎么算?
如题!
sin(-π/7)和sin(-π/5)、cos4/7 π 、cos5/8 π 怎么算?如题!
sin(-π/7)
= - sin(π/7)
sin(-π/5)
= - sin(π/5)
cos(4π/7)
= - cos(3π/7)
cos(5π/8)
= - cos(3π/8)
诱导公式的推导,如何利用公式sin(π+α)=-sinα 和sin(-α)=-sinα 得到sin(π-α)=sinα ?
sin(-π/7)和sin(-π/5)、cos4/7 π 、cos5/8 π 怎么算?如题!
化简 sin(5π/2-a) 和 sin(a-3π/2)RT
比较sin(-27π/5)和sin(43π/4)
计算,sin(π/12)-sin(5π/12)+2sin(π/8)sin(3π/8)
sin(π-a)和sin(a-π)等于多少?
sin^2 π和(sinπ)^2有什么区别?一个是平方再sin符号后,一个是在sinπ后加平方,求区别
已知sin(π+a)=-1/2,计算:sin(5π-a)和cos(a-(3π/2))
[sin(a-6π)cos(7π/2-a)]/[sin(3π+a)+sin(a-π)】=
sin(-π/3)+2sin(5π/3)+3sin(2π/3)的值为多少
①利用公式sin(π-θ)=sinθ和sin(∏+θ)=-sinθ证明:sin(-θ)=-sinθ②证明tanθsinθ∕tanθ-sinθ=1+cosθ∕sinθ③已知sinα-2cosα+1=0,α≠kπ+π∕2,k∈z求:tan(3π-α)和1∕sin2α-sinαcosα+1的值
sin(5π-α) 等于什么?
sin(-5π/4)=
sin(-19π/6)=?已知[3Sin(π+a)+Cos(π-a)]/4Sin(-a)-Sin(5π/2+a)=2,求tan a
sin0=0 sin(1/6π)=1/2sin(1/3π)=√3/2sin(1/2π)=1sin(2/3π)=√3/2sin(5/6π)=1/2sin(π)=0sin(-π)=0sin(-5/6π)=-1/2sin(-2/3π)=-√3/2sin(-1/2π)=-1sin(-1/3π)=-√3/2sin(-1/6π)=-1/2sin(7/6π)=-1/2sin(4/3π)=-√3/2sin(5/3π)=-√3/2sin(11/6π)=-1/
若(sinθ+cosθ)/(sinθ-cosθ)=2,则sin(θ-5π)*sin(3π/2-θ)等于?
若(sinα+cosα)/(sinα-cosα)=2 则sin(α-5π)·sin(3π/2-α)=?
若sinα+cosα/sinα-cosα=2,则sin(α-5π)*sin(3π/2-α)等于?